I am developing a DSPC6713B board with an ALTER CPLD. The EMIF address is very strange.
When I used the CE2n space, the corresponding address for the following VHDL code is 0xA0080000:
assign CSAD1n = ~((~CE2n)& XA20 & (~XA19)& (~XA18));
When the CE3n is used, the corresponding address for the following VHDL code is 0xB0040000:
assign user_LED1 = ~((~CE3n)& XA20 & (~XA19) & (~XA18) & XD1);
It is just very confused for me! What is the addressing method for EMIF address line EA2~EA21.
Is the EA2 corresponding the lowest address bit A0 or not?
