This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

Questions about the status of pin AOE of C6713B

Other Parts Discussed in Thread: SN74LVC16245A, TMS320C6713B

Hi,
  all.
      I am doing my project with TMS320C6713B and SN74LVC16245A. I connected the AOE(pin 75 of C6713B) to the DIR of SN74LVC16245A. My purpose is that
  1)when C6713B writes to the memory, data transmites from A bus to the B bus
  2)when C6713B reads data from memory, data  transmites from B bus to the A bus
 
     but I found in datasheet of TMS320C6713B on Page 52, the pin type of AOE is O/Z, is it means the AOE pin cannot go to H level when C6713B isn't writting?
is my connection right if I want to realize my purpose 2) ??
     There isn't Read or Write status pin in TMS320C6713B, if I want to realize the function I wanted listed above using only one pin ? How could I do?
     Thank you!

  • Keven,

    Keven74263 said:
    the pin type of AOE is O/Z, is it means the AOE pin cannot go to H level

    The O means the pin can be an output pin. The Z means it can be set to high-impedance under program control. When the pin is an output, it will drive L or H as required for the operation.

     If an output were open-drain, it would be specifically mentioned that way, such as for the DR1/SDA1 pin when used as an I2C output.

    You have a choice of signals to use for your purpose and function, so the decision will have to be based on your engineering design based on your components and the specifications for the C6713B pins in the datasheet. The datasheet and the EMIF User's Guide show timing diagrams for the various signals so that you can choose which will provide the best timing and function for your application. AOE or ARE may be most useful, but they may also have to be qualified with one of the CEn pins.

    Regards,
    RandyP

     

    If you need more help, please reply back. If this answers the question, please click  Verify Answer  , below.