AM68A: Clarification aboute memory requirement for video encoder

Frank Bergmann

Part Number: AM68A

Tool/software:

Hi experts,

in the Processor SDK Linux we have 3.7 Multimedia Video Codec. There is the statement: "The Actual Memory foot print may vary depending on the input stream.".

Can anyone please clarify this a bit more. We know that its difficult as it depends on the video size and framerate. But maybe it is possible for streams with D1 resolution (720x480, 30fps). How much memory (total and CMA) would be necessary to encode (H.264) 1, 4 and 8 streams? What is the absolute minimal memory requirement?

Thanks in advance,

Frank Bergmann

2 months ago

0 Christina Kuruvilla 2 months ago

TI__Expert 6060 points

Hi,
Due to a US holiday, the engineer responsible is currently out of office. Apologies for the delay, and thank you for your patience
Warm regards,
Christina

+1 Sarabesh Srinivasan 2 months ago

TI__Genius 17730 points

Hi Frank,

The topic of memory footprint like mentioned in the SDK docs is highly variable not only depending on the general stream parameters like resolution and fps but also the actual content of the stream and more hidden parameters like lossless, IDR period, 3DNR, etc. to name a few.

We have some internal facing formulas to determine a rough idea of the memory footprint that I can share below.

1x channel: 17.21MB

4x channel: 68.84MB

8x channel: 137.68MB

Thank you,
Sarabesh S.

0 Frank Bergmann 2 months ago in reply to Sarabesh Srinivasan

Prodigy 130 points

Hello Sarabesh,

Thanks for your answer!

These values are the memory for the encoder I guess. To estimate the whole memory requirement we have to add memory for the video stream images (for example v4l2src, v4l2h264enc, ...)?

Frank

0 Sarabesh Srinivasan 2 months ago in reply to Frank Bergmann

TI__Genius 17730 points

Yes that is correct

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AM68A: Clarification aboute memory requirement for video encoder