C6678 interrupt can't work

Can somebody help me?

Hi,

Have you enable the NMI? I haven't try your example, maybe it is already enabled somewhere in the CSL functions, but if it is not the interrupts are not served:

CSL_chipWriteIER(3|(1<<intId));

Enable int 4, NMI (bit1) and alsoset to 1 the bit0. About the bit0, I'm not sure, it is reserved and it is usually at 1.

Hi Alberto Chessa

I have tried to write 0xf3 to the IER, but still can't work!

Eric,

You create your own intcInit() function to configure the CorePac INTC, but It is not obvious to me that how you link the evenId=91 to the CorePac IntId=4.

I suggest you could try the CSL INTC functions first for the correct configuration sequence. I modified your main.c file which is attached. It should be working that a=1 after triggering the IPC interrupt.

If it is working for you,  you could try to scale it down and use your own function. But if CSL INTC function suits your application, it is still a good choice.

Sincerely,

Steven

7446.main.zip

Hi Steven

Thank you for you reply!

 I wirte the INTMUX address to link the event 91 to the INT4, The statement "REG(0x01800104) = 0x0706055B;" in function IntcInit() do the job.

 I've test the INTC example and it can work.        I want to know if the CorePac interrupt can triggered by set the EVESET .

Eric,

The C66x INTC structure is similar as C64+ INTC. Please take a look at the following thread

http://e2e.ti.com/support/dsp/tms320c6000_high_performance_dsps/f/112/t/62917.aspx#226509

As Brad said "Writing to the EVTSET register will set the corresponding EVTFLAG bit.  However, that register is part of the event combiner and would not be "in the path" of a direct mapped interrupt."

Hope it helps.

Sincerely,

Steven