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Does multplication cost more than addition?

Robert W
Mastermind 7100 points

Hi,

I am implementing an algorithm. The following reference (below dot  line) is about the similar algorithm using TI 6201. What it said seems multiplier costs more than addition. I have some programming in C for TI 6713. I remember that TI DSP multiplication can be done in one cycle. It needs more instruction fatch? How do you think about that? Thanks.

 

..................

A  so called Q-format representation consisting of 16

bits for both integer and fractional parts is employed

for the fixed point implementation. Overflow is

avoided via  clipping. Reduced complexity is achieved

by avoiding division or multiplication operation even

for the lookups. Interval size is specified as the power

of two to replace multiplications with shift operations.

  • 0
    TI__Guru* 84110 points

    Robert,

    The context is confusing here, since this was originally posted in the C64x Forum, the question is about the C6713, the Tag is for the 6211, and you reference some unknown document about the C6201.

    If you have some programming in C for the C6713, please compile it and run it and see if the performance is what you require.

    I am not sure what else to discuss here. If you have more specific questions, please re-state your questions for the processor of choice and give us document references if you are asking what we mean in some TI document.

    Regards,
    RandyP