In document "SPRUER9D–November 2009", there is a description in page 25, Figure 13 regarding stuffing blank data to align the 10 bit and 11 bit raw capture mode, it is a little confused about the notation "000000&pixel 0[9:0]" in 10 bit mode, and "0000 & pixel 0[11:0]" in 12 bit mode. I assumed that all the 0-7 pixels are same as in the top column as 8 bit mode, only the extra 2 bits (in 10 bit mode) or 4 bits ( in 12 bit mode0) need extra room to store, my question is :
1) where are those extra data space? Adjacent to the 8 bit mode data location, how the physically aligned?
2) what are those bits? how to combine those extra bits make pixel0~ pixel3 in 10/12 bit mode, I am not quite sure why needs extra 4 pixels to make 10 bit mode?