8168 GPMC as interrupt pin

Mohamed Asif

Hello

we are using 8168 ic and we are using pin GPMC_A27/GP0[20] as interrupt pin for octal device (xr16l788) but we are not able to get the interrupt in ISR. what will be the problem.

Regards

Asif

over 12 years ago

0 Pavel Botev over 12 years ago

TI__Guru**** 170625 points

Hi Asif,

Are you using EZSDK? If yes, make sure you are on the latest one 5.05. What is the value of your PINCTRL233 register (at address 0x48140BA0) ?

Please have a look in this wiki:

http://processors.wiki.ti.com/index.php/Configuring_GPIO_Interrupts

Regards,

Pavel

0 Mohamed Asif over 12 years ago in reply to Pavel Botev

Intellectual 580 points

Hi Pavel

we are using DVRRDK version DM8168_DVRRDK_V03.00.00.00.

pin = 20;

                gpio_direction_output(pin, 0x1);
                gpio_export(pin,true);
                status = gpio_get_value(pin);
                printk("status = %d\n",status);

                irq = gpio_to_irq(pin);
                if(irq < 0)
                {
                 printk("error irq =%d\n",irq);
                 gpio_free(pin);
                }
                else
                {
                 printk("success gpio_to_irq irq = %d\n",irq);
                 XR788_IRQ = irq;
                }

                 set_irq_type(irq,IRQ_TYPE_EDGE_FALLING);

ret = request_irq(up->port.irq, serialxr788_interrupt,IRQF_SHARED, "xrserial", i);

Regards

Asif

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8168 GPMC as interrupt pin