Trying to modify UBL memory map to reserve first 16bytes of internal RAM at 0x80000000

Hi,

I'm working with OMAP-L138 and AM1808.

I need an area of RAM that survives warm reset.  My idea was to use the On-Chip RAM at 0x80000000 but I discovered UBL uses this memory.  So looking at ubl.cmd I see several things that start at 0x80000000.  Not 100% understanding how each of these were used, I simply tried to move everything that started at 0x80000000 to 0x80000010 as in the following:

/*IRAMStart  = 0x80000000;*/
/*bth - we are reserving the first 4 long words for bootcount */
IRAMStart  = 0x80000010;
/*IRAMSize   = 0x00020000;*/
IRAMSize   = 0x0001FFF0;

DDRStart   = 0xc0000000;
DDRSize       = 0x02000000;

/*DRAMStart  = 0x80000000;*/
DRAMStart  = 0x80000010;
/*_DRAMSize  = 0x00020000;*/
_DRAMSize  = 0x0001FFF0;

STACKStart = IRAMStart + IRAMSize;

_NAND_EMIFStart = 0x62000000;
_NOR_EMIFStart = 0x60000000;

MEMORY
{
/*  ARM_INTERNAL_RAM (RWXI):    origin = 0x80000000    length = 0x00010000 */
  ARM_INTERNAL_RAM (RWXI):    origin = 0x80000010    length = 0x0000FFF0
  SDRAM     (RWXI):    org=0xc0000000    length = 0x02000000
}

SECTIONS
{
/*  .boot: load = 0x80000000 */ 
  .boot: load = 0x80000010 
  .text: load > ARM_INTERNAL_RAM
  .data: load > ARM_INTERNAL_RAM
  .bss:     load > ARM_INTERNAL_RAM
}

.. but I still have a problem.  When UBL starts u-boot, I can write a value to say 0x80000000 and then type 'reset' on the u-boot command line and the value I wrote is gone.  I've read in the data sheet that the contents of internal memory are retained on warm boot.

Any idea what the problem could be?  Am I going down the wrong road by modifying the ubl.cmd file the way I have?

Thanks!

Regards,

Brian