Hi TI engineer,
As described in SRIO User Guide Chapter 2.8, when C6678 works in little endian, endian-conversion will be handled by the peripheral.But I cannot understand the process clearly.
The figure shows how 128 bit in VBUS changed to the data stream in SRIO packet.I want to know if B0 - B15 is the memory address?For example,if there is the data in the memory:
Addr1 Addr1+1 ...... Addr1+15
0x0 0x1 ...... 0xf
And we assume the swap mode is mode A. Then what will the data stream be in the packet?Who is the first Data in the port?
Thank you very much,looking forward to the reply.
Regards.