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Question about total address space of EMIF

This might be simple question.

According to AM335x datasheet, Memory device capacity is up to 1G Byte addressability.

But, AM335X has only 16 Bit address bus[A0-A15] and 3 bit bank address[BA0-BA2]

so total addressability (for external memory) should be 2^19 = 512K Byte.

So, I want to know how to full 1G Byte DDR2/3 Memory in my design.

Best Regards

Hak-Jin Jeong

 

  • Hi Jeong,

    DDR address lines do not drive physical addresses. These lines are used for driving DDR commands, and also row and column addresses. If you open a DDR datasheet you will see that there are row and column address bits in it. So total addressable memory is rows*columns*banks.