C6678 interrupt registers

Mark Samson

i've some doubt about the Interrupt Controller of the C6678

From Table 9-3 in SPRUGW0C i've seen the addresses of the registers for the interrupt controller... bot how can i distinguish this registers for the 8 cores of the DSP? There is only a single set of registers...

For example: writing to 0x01800104h (INTMUX1 Interrupt mux register 1) which of the 8 cores will affect?

over 10 years ago

0 Ganapathi Dhandapani95 over 10 years ago

TI__Mastermind 28085 points

C66x CorePac Registers address is common for all the cores. For more information refer chapter9 "Interrupt Controller" on CorePac User Guide. Refer below wiki link for Configuring the CorePac Interrupts.

http://processors.wiki.ti.com/index.php/Configuring_Interrupts_on_Keystone_Devices

Thanks,

0 Mark Samson over 10 years ago in reply to Ganapathi Dhandapani95

Intellectual 355 points

So if the register set is common i have only a total of 12 configurable interrupts commons to all the 8 cores?
Didn't each core have his own set of 12 configurable interrupts?

0 one and zero over 10 years ago in reply to Mark Samson

TI__Mastermind 18146 points

Yes, each core has its own 12 interrupts.

Kind regards,
one and zero

0 ran35366 over 10 years ago in reply to one and zero

TI__Genius 12805 points

This is what I think

If you look at table 6.1 of http://www.ti.com/lit/ds/symlink/66ak2h12.pdf - the data sheet and look at address 00 0080 0000 you see that this is the local address of L2. The SOC view says that this is L2 (even though for the SOC to look at the L2 of any core it must use a different address – the global address)

Similarly I think that address 0x0180 0104 is a local address and not global address, but unlike L1 or L2, there is no global address for these registers.

IN order to prove it just select core 0, change on of the registers in addresses 0x018001XX and then select any other core and see if you see the change

Does it make sense?

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C6678 interrupt registers