How to invert/handle level-triggered interrupt?

Hi,
You can call the ISR handler depends on the IRQ signal.
Ex:
"irq_set_irq_type(irq no, IRQ_TYPE_EDGE_FALLING)"

What is your kernel version ?
Depends on the version, API may get change, check "linux/irq.h"

Hi Titus,

I am using linux 3.12.10. I already tried doing that but the behavior is the same. here is the sequence of function calls:

irq_set_status_flags(irq, IRQF_ONESHOT);
irq_set_irq_type(irq, IRQ_TYPE_EDGE_FALLING);
disable_irq(irq);
request_any_context_irq(irq, isr, IRQF_SHARED, desc, data);
enable_irq(irq);

I have tried a number of flags on request_any_context_irq but the result is the same, the ISR gets called all the time blocking everything and the calls to ISR only stops when the button has been pressed (sincethe signal becomes active high). Are there other functions calls that I can do to reverse the call so that the ISR will be called only when the signal is active high?

Regards,
Marlon

Hi,
You meant that ISR must call when the signal is high ?
Have you tried this API ?
irq_set_irq_type(irq, IRQ_TYPE_LEVEL_HIGH);

Hi Titus,

Yes, the ISR must be called when the signal is high. I have tried other flags as well (e.g. IRQ_TYPE_EDGE_RISING, IRQ_TYPE_EDGE_FALLING, IRQ_TYPE_EDGE_BOTH, IRQ_TYPE_LEVEL_HIGH, IRQ_TYPE_LEVEL_LOW) but it seems the flags are ignored, the behavior doesn't change. I always get the interrupt and it only stops when the button is pressed.

Regards,
Marlon

Using shared interrupt ?
Try this.
request_any_context_irq(irq, isr, IRQ_TYPE_LEVEL_HIGH, desc, NULL);