Socket Sendto() real-time udp stream

Taras Kolesko

Hello again.

I'm trying to make my board (TMDXEVM6670L) to send packets to my PC, using following code:

for(;;)
	    {
	        tmp = sizeof( sin1 );

	        i = (int)recvnc( s, (void **)&pBuf, 0, &hBuffer );
	        printf(pBuf);
	        printf("\n");

	        poutbuf = outbuf;

	        if( i >= 0 )
	        {
	        	for (j = 1; j < 100; j++)
	        	{
	        		outval = j;
					ltoa(outval, poutbuf);//
	        		if (j < 10)
	        		{
	        			sendto(s, poutbuf, 1, 0,(PSA)&sin1, sizeof(sin1) );
	        			printf(poutbuf, "\n");
	        			platform_delay(40000); // 0.04 sec
	        		}
	        	 	if (j >= 10 && j <100)
	        		{
	        			sendto(s, poutbuf, 2, 0,(PSA)&sin1, sizeof(sin1) );
	        			printf(poutbuf, "\n");
	        			platform_delay(40000);
	        		}
	        		if (j >= 100 && j < 1000)
	        		{
	        			sendto(s, poutbuf, 3, 0,(PSA)&sin1, sizeof(sin1) );
	        			printf(poutbuf, "\n");
	        			platform_delay(40000);
	        		}
	        		if (j >= 1000 && j < 10000)
	        		{
	        			sendto(s, poutbuf, 4, 0,(PSA)&sin1, sizeof(sin1) );
						printf(poutbuf, "\n");
						platform_delay(40000);
	        		}
	        	}
	            sendto(s, 0, 0, 0,(PSA)&sin1, sizeof(sin1) );
	            recvncfree( hBuffer );
	        }
	        else
	            break;
	    }

The problem is, that operations do not work inside the loop, until the loop itself does not end. I need to send a large amount of packets like that, and i don't know why this is happening. Could you please help me to understand, how to rework this code properly?

over 9 years ago

0 Titusrathinaraj Stalin over 9 years ago

TI__Guru** 116100 points

Dear Taras,

The problem is, that operations do not work inside the loop, until the loop itself does not end. I need to send a large amount of packets like that, and i don't know why this is happening. Could you please help me to understand, how to rework this code properly?

I hope this loop will not end.
Where you are decreasing the value of "i" and also for loop is in infinite loop.
Can you please try the following code.

for(;;)
{
tmp = sizeof( sin1 );

i = (int)recvnc( s, (void **)&pBuf, 0, &hBuffer );
printf(pBuf);
printf("\n");

poutbuf = outbuf;

if( i >= 0 )
{

//Titus : Use it here or last line
// i--;

for (j = 1; j < 100; j++)
{
outval = j;
ltoa(outval, poutbuf);//
if (j < 10)
{
sendto(s, poutbuf, 1, 0,(PSA)&sin1, sizeof(sin1) );
printf(poutbuf, "\n");
platform_delay(40000); // 0.04 sec
}
if (j >= 10 && j <100)
{
sendto(s, poutbuf, 2, 0,(PSA)&sin1, sizeof(sin1) );
printf(poutbuf, "\n");
platform_delay(40000);
}
if (j >= 100 && j < 1000)
{
sendto(s, poutbuf, 3, 0,(PSA)&sin1, sizeof(sin1) );
printf(poutbuf, "\n");
platform_delay(40000);
}
if (j >= 1000 && j < 10000)
{
sendto(s, poutbuf, 4, 0,(PSA)&sin1, sizeof(sin1) );
printf(poutbuf, "\n");
platform_delay(40000);
}
}
sendto(s, 0, 0, 0,(PSA)&sin1, sizeof(sin1) );
recvncfree( hBuffer );
//Titus
i--;

}
else
break;
}

0 Taras Kolesko over 9 years ago in reply to Titusrathinaraj Stalin

Expert 1730 points

Ok, that i can understand. But why the "Sendto" functions are not responding? When i'm using them once, they are executing like i need, but they are not working inside loop. Why is this happening?

0 Titusrathinaraj Stalin over 9 years ago in reply to Taras Kolesko

TI__Guru** 116100 points

Firstly, try to send around 100 packets then increase it and test.

Try this code.

for(;;)
{
tmp = sizeof( sin1 );

i = (int)recvnc( s, (void **)&pBuf, 0, &hBuffer );
printf(pBuf);
printf("\n");

poutbuf = outbuf;

if( i >= 0 )
{

//Titus : Use it here or last line
i--;

for (j = 1; j < 100; j++)
{
outval = j;
ltoa(outval, poutbuf);//
if (j < 10)
{
sendto(s, poutbuf, 1, 0,(PSA)&sin1, sizeof(sin1) );
printf(poutbuf, "\n");
platform_delay(40000); // 0.04 sec
}

}

}

else
break;

break;

}

0 Taras Kolesko over 9 years ago in reply to Titusrathinaraj Stalin

Expert 1730 points

While step-by-step debug, sendto "slips" without performing and returns nor result neither error...

0 Titusrathinaraj Stalin over 9 years ago in reply to Taras Kolesko

TI__Guru** 116100 points

Okay, let me try it on my machine and update you.

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Socket Sendto() real-time udp stream