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C6748 HPI

Bruno Scherrer
Intellectual 820 points

Hi,

Actually I managed to write a piece of code for initializing the HPI.

My first test is to try to read the HPIC reg but it doesn't seem to work so well.

I have a quite simple question to start with :

Does /HPI_READY need a pull-up resistor ?

if yes is it possible to use an internal pull-up ?

rem : I tagged 6747 UHPI although I'm working on a C6748 but since it's the closest one... [ed: fixed]

 

 

 

  • 0
    TI__Guru* 84110 points

    Bruno Scherrer said:
    Does /HPI_READY need a pull-up resistor ?

    No. HRDY will be a driven pin when configured for UHPI operation.

    But this implies that you have not seen it go high. Can you connect a scope or [preferably] a logic analyzer to the UHPI control pins to see if they seem to be toggling the way the datasheet and User's Guide show? And if you want more confidence in the pull-up question, tack a 20K resistor to it just to be sure.

    I would recommend finding some example code that initializes the UHPI or looking for detailed instructions in the User's Guide to make sure you are doing everything to get the UHPI configured correctly, including PINMUXes and PSCs and such.