Manually generate interrupt event

Sajedul Alam

I want to manually generate Event 65 as an interrupt event to the CPU (from the C6455 System Event Mapping, 65 = GPINT14 GPIO interrupt)

I do this in the code:

INT_CTRL_REGS->EVTSET[2] = 0x2; //ES65

Is this enough? I must be missing something since the interrupt isn't getting generated (HWI never fires)

over 15 years ago

0 Pavan Bhave over 15 years ago

Intellectual 700 points

Have you mapped the event to an interrupt. Use the HWI section in the configuration GUI of CCS.

0 Sajedul Alam over 15 years ago in reply to Pavan Bhave

Prodigy 50 points

yes. Here is the GUI config:

bios.HWI.instance("HWI_INT7").interruptSelectNumber = 65;
bios.HWI.instance("HWI_INT7").fxn = prog.extern("MyIsr");
bios.HWI.instance("HWI_INT7").useDispatcher = 1;
bios.HWI.instance("HWI_INT7").interruptMask = "all";

I also enable the IER using:

C64_enableIER(C64_EINT7);

This above mechanism worked for me for other pre-defined events (e.g. DMA completion etc), but not for this GPIO interrupt. I wonder if there's anything special to do there.

0 Pavan Bhave over 15 years ago in reply to Sajedul Alam

Intellectual 700 points

Thats a bit odd...

Hope you have configured the GPIO interrupt polarity etc etc .. but in theory that should have no effect as you are manually setting the event.

Should work in theory.

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Manually generate interrupt event