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My question relates to topology of laser diode drivers, not LED drivers, but didn’t know where else to post it. I am trying to design a laser diode driver for TOF application and was thinking about using the capacitive discharge to generate a very short and fast rise current pulse. I also thought about the inductive discharge topology.
Then I read the SBAA209A app note and I thought the “shunt switching” circuit mentioned there is similar to the inductive discharge circuit I pictured above. However after watching this video by Larry Li: https://training.ti.com/3d-time-flight-illumination-subsystem-design-and-component-selection?cu=1127769 I started to have doubts this is the case. In the video the duty cycle is said to be 50%.
I am not sure what current waveforms to expect from the “shunt switching” circuit. Is there an app note describing this? I tried searching the TI website, but no luck. I would highly appreciate any feedback.
Thank you,
Michael
Hi Michael,
I am looking into this and will get back sometime this week.
Best,
Alex
I am only interested in driving the laser diode with a short (20-50nsec), fast rise time (1-2nsec) current pulse. Aiming for 30-50A.
Michael,
Yes. Using the capacitive discharge method would give you better efficiency and probably a sharper response time(rise time and fall time). However, if you want a flat illumination waveform, you should use the series inductor "shunt switching" method. Owing to your high current values and low duty cycle, you would probably have a lot of conductive losses. If not, there would still be losses in charging and discharging the inductor to avoid the conductive losses.
Hope this answers your query.
Regards,
Subhash