This will not work because the voltage divider does not leave any current for the charge pump or for any other devices connected to the ±10 V supplies.
What is the actual problem you're trying to solve? Why do you need ±10 V, and how large is the load?
Hi Tom,
Pls double check the application with customer at first. Looking forward to your reply. Thanks.
Aurora
Hi Aurora and Clemens,
My application uses the LMC7660 to generate a -10V power supply for the TMUX7234, with a current of approximately 10mA.
Can I use a 10V Zener diode to clamp Vin at 10V to generate a -10V output? Or do you have any other recommended solutions?
Thanks!
You can use a Zener, but then you have to remove R801. R800 must be sized to provide enough current for the Zener, the LMC7660, and the TMUX7234.
Hi Clemens,
The Zener diode I have selected has the following specifications:
Assuming the LMC requires an output current of 10mA,
Plus the Zener diode's current consumption of 5mA,
The resistor value is calculated as:
R = (14V - 10V) / 5mA = 267Ω
Is this suitable?
Thanks!
The LMC itself might need up to 400 µA. (14 V − 10 V) / (5 mA + 400 µA + 10 mA) ≈ 259 Ω.
Where do you get that 10 mA value from? The TMUX7234's supply current is much less than 1 mA, and independent from the current that flows through the switches.
(The Zener voltage will vary with current, so if you care about a stable output voltage or want to save power, better use the TL431.)