Tool/software: TI-RTOS
Hello,
Looking through the documentation for HeapBuf, I see that the call below allocates a certain size of memory (Blocks size?) based on an align property, however, in the documentation it also states that "All alignment is handled in the create, therefore the align argument in alloc is ignored". Does this mean that any value I put into the third argument is irrelevant? Also, if I decide to set the size of the HeapBuf_Params.blockSize before memory allocation, why should we be required to pass argument #2 of SizeT size? Thank you!
Ptr HeapBuf_alloc(HeapBuf_Handle handle, SizeT size, SizeT align, Error_Block *eb);