ON THE ABOVE PART
WITH PIN#6 AT A REF. VOLTAGE FROM THE OUTPUT OF A OP-AMP OF +2.50 VDC AND A SINEWAVE RIDING ON THE REF LEVEL
OF 1.25 VAC PK-PK.
ON PIN#7 IS THE OUTPUT OF A OP-AMP THAT WILL BE THE ERROR AMP FOR THE FEEDBACK VOLTAGE AND THE + INPUT OF THE OP-AMP IS AT +2.50 VDC AND THE - INPUT WILL BE WHERE THE FEEDBACK SIGNAL WILL GO .
NOW LETS SAY WE HAVE NO SINEWAVE REF INTO PIN#6 THE OUTPUTS OF THE DEVICE SHOULD BE TWO SQ. WAVES AT THE SELECTED FREQ. AND AS WE START TO APPLY THE SINEWAVE INTO PIN#6 THE OUTPUTS START TO MODULATE AT THE REF. FREQUENCY.
BOTH OF THE OUTPUT DRIVE SIGNALS AT PINS# 17 AND 24 WILL GO INTO HIGH VOLTAGE HALF BRIDGE DRIVERS AT +200 VDC WHICH WILL BE ISOLATED BY A PLANAR TRANSFORMER AND THE OUTPUT OF THE POWER TRANSFORMER WILL GO THRU LOW PASS FILTERS AND WE HAVE THE SINEWAVE AT THE OUTPUT VOLTAGE LEVEL .
WE SAMPLE AND DIVIDE THE OUTPUT DOWN TO A REF LEVEL AND FEED IT BACK TO THE - INPUT OF THE ERROR AMP NOW WE HAVE A CLOSED LOOP AND REGULATION,NOW DO YOU AGREE WITH THIS .
AND ALSO THE FREQ SELECTED WILL IT BE DIVIDED IN HALF AT THE OSC INTERNALLY ,ARE LETS SAY WE USE A EXTERNAL CLOCK AT 200 KHZ INTO PIN#4 WILL THE RAMP BE AT 200 KHZ ARE AT 100 KHZ. SEE IF YOU CAN LET ME NO ON THE ABOVE IDEA AND GIVE ME YOUR FEEDBACK PLEASE THANKS,
WILLIE