I would like to know how the PGA is affected by a DC voltage or bias voltage.
For example, please consider the following...
== Scenario 1 ==
ADS1115 Connected in SE mode (CH1- grounded).
A 1uF capacitor is used to AC couple a low-frequency signal to the CH1+ input.
A 10K resistor is connected from the CH1+ input to a voltage reference of +2.05V. This voltage is used to bias the converter in such a way as to allow both positive and negative voltage swings to be measured.
If no signal is present (just the 2.05V bias) what will the output of the converter be when the PGA is configured for 1X, 2X, 4X, 8X, 16X?
Is the GAIN centered AROUND the 2.05V bias (the midpoint of the FS reading of the converter)? Or, will the gain of the PGA affect the output of the converter because it is amplifying the DC bias voltage?
== Scenario 2 ==
Assume the ADS1115 is connected in DIFFERENTIAL mode as follows...
Low frequency signal is AC coupled to the CH1+ input via a 1uF capacitor.
A 2.05V DC bias is applied to the CH1+ input with a 10K resistor.
The CH1- input is connected directly to the 2.05V bias voltage.
Would this work? It would seem that the AC input voltage would "swing" around the +2.05V DC bias voltage.
Would this method allow me to take advantage of all 16 bits (positive AND negative) readings?
How would the gain of the PGA affect my readings? Essentially, I would like to use the PGA to amplify the AC signal as necessary WITHOUT the DC bias affecting the measurement.
Which technique is better (if any)?
Thanks in advance.