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TPS25942xEVM-635 - About ORing circuit & DEVSLP pin

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Guru 21045 points

Hi Team,

 

Our customer are evaluating the ORing circuit at the following conditions.

 

[Conditions]

-Battery1 = 7.6V

-Battery2 = 7.58V

-J4 & J9 = High

-Other jumper is default

-R9 remove

- 270kohm is connected to parallel to R20

 

However, they were confronted with the following problem.

Could you please let us know if you have any solution?

 

[Problem]

"Battery1" is charged when “Battery1=7.6V” and “Battery2=7.58V”.

However, they would like to prevent this phenomenon.

 

 

I believe that we can solve this problem if we use this device with the Non-ideal Diode mode.

So, we have to connect "Pin1_CTRL-1" and "VIN1" of Jumper6.

Is my understanding correct?

 

 

And, I have one more question.

I believe that “DEVSLP pin” is “DMODE pin”.

why are mention contents different from the datasheet?

 

 

Regards,

Kanemaru

  • 0
    TI__Intellectual 865 points

    Hi Kanemaru-san,

    The reverse protection comparator threshold for TPS25942 is -10mV (typ) and -15mV (min). With the present setup (battery 1 at 7.6V and battery 2 at 7.58V), the differential voltage across IN and OUT of theTPS25942 will be close to -10mV. This circuit should turn OFF when battery 2 is below 7.57V.

    However to intentionally break this power path one other way can be by connecting Pin1_CTRL-2 to VIN2 at jumper 10.

    In the EVM schematic, the DEVSLP pin should be renamed as DMODE. It's a mistake.

    Regards,

    Dilip

  • 0 in reply to Dilip Jain
    Guru 21045 points

    Hi Dilip-san,

     

    Thank you for your prompt reply!

    I understand that this device(U2) become the Non-ideal Diode Mode if they connect "Pin1_CTRL-2" and "VIN2" of Jumper10.

    As a result, the path of the charge current from "Battrey1" to "Battery2" disappears.

    Could you please let us know if there are any mistakes in that?

     

    Regards,

    Kanemaru