Part Number: LM43600-Q1 At the moment, I am trying to use a DC-DC converter to lower my voltage and boost my current. I have a power supply of 15 V with a maximum of 300 mA. What would the new maximum current that I can output if the voltage output is…
Hi,
Yes according to the datasheet it seems to be ok to keep the EN pin floating.
Another alternative is to use a part where EN can be tied directly to VIN such as
LMR23610-q1 or LM43600-Q1
www.ti.com/.../LMR23610-Q1
www.ti.com/.../LM43600…
Part Number: LM61495-Q1 Other Parts Discussed in Thread: LM61495 , LM43600 Hello,
Need Unencrypted PSPICE model (.lib) of LM61495-Q1 for Circuit simulation using Ansys tools. As i am performing Radiated emission simulation for our PCB, hence required…
Part Number: LM43600 The LM43600PWPR or LM43600QPWPR-Q1 is used in some of our products to convert 28V to 5V or 3.3V.
At the moment, our purchasing department cannot source the 0.5A variant but are able to source the 2A variant: LM43602PWPT.
I have…
Part Number: LM43600 Other Parts Discussed in Thread: LM53600-Q1
Hi all Would you mind if we ask LM43600? In case of SYNC input(external clock input), if the light is light load, will the mode be PFM mode? We would like to use forced PWM mode in case…
Other Parts Discussed in Thread: LM46000 , LM43600 , LM22678-Q1 Hi,
I need a 12VDC to 5VDC 1 Ampere step down converter with surge protection.
Kindly advise if there are devices which fulfil this requirement.
Regards
Atul Bhakay
Hello
As I mentioned, the issue arises during a fault condition.
If the output is shorted, then the inductor current is equal to the current limit, regardless of load current.
Under those conditions your inductor should be rated for the current…
SNVA816_Anon-A_FinalDraft.pdf Two changes between A and non A versions:
1. Roughened lead frame
2. Improvement for PFM at light load and low vin conditions
a. A version removes some of the variability we see in PFM entry point vs. the non A for…
I have attached two app notes that should help to answer your questions:
1. Yes you will not get as much as 2A from the regulator in the inverting mode; see app note on how to calculate
2. Yes
3. Yes; see app notes for ideas
4. Yes
5. Yes; see…
