Hi TI Expert,
We notice the VFAILSAFE(VOUTP - VOUTN) will be -2.6V if following condition is fulfilled.
Is there any way that we can keep the VOUTP-VOUTN as 0V even the VDD1 power is missing?
Or the only way is to disable the VDD2 once we identify the VDD1 dropped?
Since the output voltage depends on the VDD2 so once we remove it, the VOUTP-VOUTN should be 0V.
Kindly let us know if you have a better suggestion.
Maybe add a voltage bias circuit on the output side as below?
