VOCM provides an output of supply/2 if left unconnected, zero if grounded, and voltage input level if voltage connected
the offset if applied after the gain
is that correct?
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VOCM provides an output of supply/2 if left unconnected, zero if grounded, and voltage input level if voltage connected
the offset if applied after the gain
is that correct?
Hi Chris,
Below is the input circuit of Vocm pin.
If left unconnected (floating), the internal resistor divitor will set the output common mode voltage to mid supply.
This can be overdriven by an external source given it has sufficient current drive strength. In this case the output common mode voltage will follow the voltage at VOCM pin.
Regards
Anant
What if it is grounded, then zero offset?
Also, which is applied first, gain or offset? For example if my offset is 2.5V and gain is 2 and I feed in a signal of 1.5V, is it 1.5*2+2.5=5.5V or (1.5+2.5)*2=8V
If VOCM is connected to ground, then the common-mode voltage is ground. (This device does not have a GND pin and does neither know nor care where your ground is.)
A differential input of zero results in both outputs at VOCM. So the gain must be applied first.
you stated "so the gain must be applied first"
to confirm, if my offset is 2.5V and gain is 2 and I feed in a signal of 1.5V, the output is 5.5V: it 1.5*2+2.5=5.5V. (output=input*gain+offset) Is that correct?
Hi Chris,
You are correct that the output would be equal to the input * gain then the Vocm voltage is added but not gained.
Thanks,
Nick