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OPA855: Is this Op-amp capable of driving output to 0V ?

Part Number: OPA855


Tool/software:

I am using an Opamp OPA855 in non-inverting configuration in my schematic. It cannot drive output to 0V. With input at 0V, the output is stuck at 1V. Would you be able to verify if its expected ? I am attaching a snapshot of the schematic below.

 

If this is not a rail-to-rail op-amp, would you provide a pin compatible rail-to-rail op-amp with same package type ?

Regards,

Ganesh

  • Hello Ganesh,

    The OPA855 is not a rail-to-rail amp. Unfortunately I was not able to find a replacement that is rail-to-rail and the same package type. If you can accommodate a different package, let me know and I'll look for it.

    If you are able to configure the system in split supply instead, you could get a 0V output without switching the part.

    There were a couple other things I wanted to mention about the design you sent. This part is decompensated, and has a minimum stable gain of 7 V/V. Stabilizing it at a lower gain is possible but will take more design. If you are replacing the part and need the 3 V/V gain you showed, look for a unity gain stable part.

    Also note that the datasheet recommends an Rf = 453Ω. Using a resistor that's much higher, like 20kΩ, may interact with the input capacitance of the amp and destabilize the system. It will also increase noise and worsen some other datasheet specs. I would suggest using something more on the magnitude of the suggested Rf if possible.

    Let me know if you have any questions or if I can help with anything else.

    All the best,

    Hypatia

  • Hi Hypatia,

    Thank you for your response. Assuming I make the circuit stable with R1=100 ohms and Rf=700 ohms with a closed loop gain of 7 V/V, What is the lowest voltage the OPA855 can drive in this schematic configuration?

    Regards,

    Ganesh

  • Ganesh,

    The lowest output voltage would still be the 1V in the datasheet, unfortunately. The only way to reach 0V on this part would be to change the sources. You would need to decrease the negative source (Vs-) to at least -1V, and decrease Vs+ to stay within supply range.

    Let me know if you have any questions.

    Thank you,

    Hypatia