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INA233: INA233AIDGST

Surya Bharathi
Prodigy 30 points
Part Number: INA233


Tool/software:

Hi,

I have been using INA233AIDGST current sensor to read the 5V input voltage and Max 5A load current but i couldn't read any current consumption.

The shunt resistor value which i have used is 0.005E power rating of 0.25W. Is this the correct power rating to read the 5A load current? if not kindly suggest me the respective power rating value to read the Max 5A load current.

I have attached the schematic diagram of the current sensor for your reference. Kindly refer the attachment

  • 0
    TI__Mastermind 27750 points

    Hello Surya,

    Surya Bharathi said:
    I have been using INA233AIDGST current sensor to read the 5V input voltage and Max 5A load current but i couldn't read any current consumption.

    In order to have a valid current result, you need to set the MFR_CALIBRATION register first. It would be good to verify that you can read other registers successfully as well, so that can be tested on the TI_MFR_MODEL and TI_MFR_ID registers. If you still aren't getting anything for the current register (89h), try reading the voltage register (MFR_READ_VSHUNT) to verify you have a valid shunt voltage.

    Surya Bharathi said:
    The shunt resistor value which i have used is 0.005E power rating of 0.25W. Is this the correct power rating to read the 5A load current? if not kindly suggest me the respective power rating value to read the Max 5A load current.

    The power dissipated over the shunt resistor will be R*I^2 = .005 * 5^2 = 0.125W, so a resistor with 0.25W should work just fine.

    Regards,

    Mitch

  • 0 in reply to Mitch M
    Prodigy 30 points

    does the circuit design of the current sensor correct or not or should i have to change in the schematic?

  • 0 in reply to Surya Bharathi
    TI__Mastermind 27750 points

    Hello Surya,

    The schematic is good. I will note that for the shunt measurement you have is only using 25mV out of the full-scale 81.92mV. So, you could increase accuracy by increasing your shunt resistor size, but that will also use more power, so it's up to you depending on your design requirements.

    Regards,

    Mitch