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Low Side Current Measurement

Other Parts Discussed in Thread: INA214, INA213, TINA-TI, INA326, ADS1114, INA226

Hello, I want to use a current shunt monitor (INA214) with a shunt resistor of 0.000167 ohms with a current passing through of -300A to 300A this correspond to a voltage drop of 50mV. Is it possible to use the current monitor on low side and read a bi-directionnal voltage from -50mV to 50mV?

Thank you

  • Alexandre Imbeault said:

    Hello, I want to use a current shunt monitor (INA214) with a shunt resistor of 0.000167 ohms with a current passing through of -300A to 300A this correspond to a voltage drop of 50mV. Is it possible to use the current monitor on low side and read a bi-directionnal voltage from -50mV to 50mV?

    Thank you

    Hello Alexandre,

    I'm not sure whether 0.0000167 ohm shunt is available.. seems to be a non standard value. Correct me if I'm wrong.

    Why don't you consider Hall effect current sensors for your application ?

    Regards,

    JayantD.

  • Thank you for your answer Jayant,

    If you look at Murata shunt resistor 3020-01102-0 you will see that it's a 0.000167 ohms resistor rated for 300A/50mV. It seems logical because 0.000167*300 = 50mV.

    I have already consider Hall Effect and according to my research, I can't have the accuracy I need with these current sensor. For several days I looked for the best solution for my problem and I think shunt current sensor would be the best. Correct me if I'm wrong because I begin in the field of electric vehicule.

    I need a precision around 100mA to evaluate correctly the State Of Charge of my batteries. And I don't need to be isolated that's why I though of shunt current sensor.

    Could you help me out with this problem?

  • Hello Alexandre,

    The output voltage swing of the INA21x family is from Vgnd+50mV to (V+)-200mV.  If you're sensing bi-directional current you should pedestal your output voltage with the REF pin.  So, care must be taken to ensure that your supply voltage (V+) can provide ample output voltage swing for your current range (-300A to 300A).

    I have attached a TINA-TI simulation that gets you started.  I set V+=10V and Vref=5V to accommodate your shunt resistor.  An alternate option would be to use the INA213 (G=50V/V) and set V+=5V and Vref=2.5V.

    As the load current changes direction (or crosses 0A), the shunt voltage will also cross 0V.  It is during this transition that the solution will have the most error as contributed by the offset voltage of the device (+/-60uV RTI for the INA214).  Since the common-mode voltage is ~0V, CMRR will also contribute and offset voltage (RTI) of 67.5uV for the INA214.  If we RSS just these two error terms we have ~90.3uV of offset.  The load current range outside of which this offset is 10% or less of the shunt voltage is +/-5.4A.  Anything outside of this range will be considered more accurate (load currents with larger magnitudes make the offset voltage less significant).  Please note this does not include errors due to things like PSRR, PCB layout, shunt resistor tolerance, temperature drift, and gain error.  Also, considering that the output can swing to within 50mV of Vgnd and 200mV of V+, the min/max ranges of the load current will be approximately -296A and 287A.

    Alexandre.TSC
  • Since the shunt resistor is in the low side (ground-referenced) why not simply use a good instrumentation amplifier? It will give outstanding accuracy with a 50mV input and its gain is easy to set accurately.

    Make sure that the shunt resistor is a Kelvin-sensing (4-wire) type!

  • Thank you for your answer Neil,

    Do you have a good instrumentation amplifier tu suggest to me for my application? And will I be able to measure bi-directionnal current?

    I'm not sure to understand how to proceed, could you please give me more information about this method?

  • Alexandre;

    I've attached a chapter of my Instrumentation Amplifier Handbook for you; check section 7.2. Bear in mind that this is a draft copy-- it never was published although it can be found all over the internet, sometimes as an earlier enedited version.

    If you use an instrumentation amplifier with bipolar power supplies, the output can swing + and - for bi-directional current measurement.

    7a- Curr Meas Apps.doc
  • Neil, Thank you for your handbook, It is really useful for better understanding.

    The problem is that I'm in an automotive case, so I only have single power supplies and I don't want to create a bipolar power supply only for this application. I would appreciate to find an instrumentation amplifier with a +5V single power supply.

  • Thank you for your answer Pete, sorry if it takes me a while to reply but I'm not sure to understand everything you said. According to what you told me, I won't be able to have a precision of +/-100mA on current measurement with the INA214. So, do you have any idea of how should I proceed? Should I use a instrumentation amplifier like Neil Albaugh suggest?

    Best regards,   Alexandre

  • Thanks, Alexandre.

    The IA shown in the Handbook is still a good one-- its common mode input voltage will go to zero and with a load of 20k the output will swing up to 50mV below the supply rail and down to within 100mV of ground.

    There are more modern 5V CMOS instrumentation and difference amplifiers that can do better than this but the TI instrumentation amplifier parametric selection guide is such a mess that I gave up trying to find a good one. Maybe a TI employee can either fix the thing or struggle through it to make a recommendation.

     

  • Hello Alexandre,

    For your particular situation none our our single-supply instrumentation amplifiers will suffice.  The closest is the INA326.  It can have an input voltage that goes 20mV below ground with a 5V supply.  You require 50mV below ground.  Please note that while the device can tolerate up to 50mV below ground, it would not be operating linearly.  Therefore I recommend using the INA21x family of devices.

    You can achieve 100mA resolution...it is dependent on your data converter.  This can be accomplished with a data converter of at least 14-bits.  I would recommend looking at the ADS1114.  Using that converter would require you to switch to the INA213...therefore I have attached an updated TINA simulation.  You will want to set the PGA on the ADS1114 to 2/3 so as to abide by the input requirement of the device.

    Another option would be the INA226.  The INA226 is a high or low-side digital current shunt monitor.  It can accept shunt voltages from -81.9175mV to 81.92mV, which is within your range.  It has an on-board 16-bit ADC and only 10uV of offset (maximum).

    Alexandre2.TSC