Other Parts Discussed in Thread: XTR115
I performed a quick test yesterday with the transmitter that has the XTR115 in it. The Ra is the load resistor in series with the XTR, and was 5000ohms. The current loop runs through both. An AC signal is applied as shown below. Vb is the voltage drop across the transmitters current loop circuit.(in the case of the 2 wire transmitter it is also the power to the transmitter). The transmitter is powered from the 5V regulated power out of the XTR115.
Since the transmitter is a 2 wire device, it runs off the current from the current loop. So, the transmitter current consumption must be less than 4mA, since that is the lowest signal level the transmitter can signal. So, when the transmitter is signaling 4mA, the NPN transistor is on, but not much. My guess is somewhere in the 1mA range.
So I performed a series of tests at different DC current signaling levels to get the NPN turned on more. Here are the results. In the 11mA results, the NPN is supplying at least 7mA of current, so it’s on pretty good. This was as high as I could go, as the resultant voltage drop across the 5000 ohm resistor lowers the voltage at the transmitter to the point where the transmitter quits working.
Zm is an approximation of the impedance magitute. Zm = R/Va x Vb.
As you can see ZM is big numbers. This is where our design is 131 ohms which is way below the minimum.
I was surprised that the impedance didn’t come down as the NPN transistor was turned on more. It appears to me that Zm is independent of the DC current through the NPN. So, where is the impedance coming from? My guess is it is the XTR115….but how???
