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Opa2614 Pspice model vs. Orcad symbol

Other Parts Discussed in Thread: OPA2614

Dear all, I try to simulate Opa2614 in Pspice from Orcad capture schematics, however, the model seems different from Orcad symbol.

There are only five pins in Opa2614 Pspice model ( one Opamp),     .SUBCKT OPA2614 + - Out V+ V-

however there are two Opamps ( 8 pins)  in Orcad symbol , and thus schematics, how to solve this problem so that the Orcad schematics can use this Pspice model?

Thank you very much!

 

 

  • Hello Bin,

    I see two possible solutions:

    1) Create a symbol that has 5 pins so that it can be matched to the model

    2) Modify the model to accomodate the Orcad symbol.  You will have to use the same nomenclature as the symbol, so the following is provided only as an example.  teh subcircuit definition should looks like

    .SUBCKT OPA2614 +A -A OutA +B -B OutB V+ V-

    with the rest of the spice model being duplicate of the original model for which you replace the + - Out from one with +A -A and OutA and + - Out from the other with +B -B OutB

    The complete spice model following this description is provided below.

    .SUBCKT OPA2614 +A -A OutA +B -B OutB V+ V-
    V_V2         V+ 10 DC .5 
    R_R1         11 10  400 
    R_R2         12 10  400 
    R_R5         21 V+  15 
    D_D1         14 13 Da 1
    D_D5         20 19 Da 1
    D_D6         22 Out Da .5
    D_D7         Out 23 Da .5
    E_E3         21 22 POLY(2) 0 19  V+ V-  -885m 1 0.5
    E_E4         23 24 POLY(2) 19 0  V+ V-  -885M 1 0.5
    R_R6         V- 24  15 
    Q_Q3         11 +A 13 NPN8 10.5
    Q_Q4         12 -A 13 NPN8 10.5
    E_E1         18 0 POLY(1) V+ V- -1  0.5  0
    E_E2         20 0 POLY(1) V- V+ 1  0.5  0
    V_V1         14 V- DC 1.10 
    C_C1         0 +A  1p 
    R_R4         19 0  1K 
    G_G2         0 19 POLY(1) 15 0 0  1m  0  0
    G_G1         0 15 POLY(1) 12 11 0  27.5m  0  0
    D_D4         19 18 DX 1
    R_R3         15 0  442.1K 
    C_C5         15 0  142.5p 
    C_C4         11 12  850F 
    I_I1         13 V- DC 1.256mA 
    C_C3         0 19  795f 
    *
    *


    V_V2         V+ 10 DC .5 
    R_R1         11 10  400 
    R_R2         12 10  400 
    R_R5         21 V+  15 
    D_D1         14 13 Da 1
    D_D5         20 19 Da 1
    D_D6         22 Out Da .5
    D_D7         Out 23 Da .5
    E_E3         21 22 POLY(2) 0 19  V+ V-  -885m 1 0.5
    E_E4         23 24 POLY(2) 19 0  V+ V-  -885M 1 0.5
    R_R6         V- 24  15 
    Q_Q3         11 +B 13 NPN8 10.5
    Q_Q4         12 -B 13 NPN8 10.5
    E_E1         18 0 POLY(1) V+ V- -1  0.5  0
    E_E2         20 0 POLY(1) V- V+ 1  0.5  0
    V_V1         14 V- DC 1.10 
    C_C1         0 +B  1p 
    R_R4         19 0  1K 
    G_G2         0 19 POLY(1) 15 0 0  1m  0  0
    G_G1         0 15 POLY(1) 12 11 0  27.5m  0  0
    D_D4         19 18 DX 1
    R_R3         15 0  442.1K 
    C_C5         15 0  142.5p 
    C_C4         11 12  850F 
    I_I1         13 V- DC 1.256mA 
    C_C3         0 19  795f 

    *
    .MODEL Da D IS=1.0000E-15
    *
    .MODEL NPN8 NPN
    + IS = 7.604E-18 BF = 1.570E+02 NF = 1.000E+00 VAF= 7.871E+01
    + IKF= 3.975E-02 ISE= 3.219E-14 NE = 2.000E+00 BR = 7.614E-01
    + NR = 1.000E+00 VAR= 1.452E+00 IKR= 8.172E-02 ISC= 7.618E-21
    + NC = 1.847E+00 RB = 1.060E+02 IRB= 0.000E+00 RBM= 2.400E+00
    + RE = 2.520E+00 RC = 1.270E+02 CJE= 1.120E-15 VJE= 7.591E-01
    + MJE= 5.406E-01 TF = 1.213E-11 XTF= 2.049E+00 VTF= 1.813E+00
    + ITF= 4.293E-02 PTF= 0.000E+00 CJC= 8.208E-14 VJC= 6.666E-01
    + MJC= 4.509E-01 XCJC=8.450E-02 TR = 4.000E-11 CJS= 1.160E-15
    + VJS= 5.286E-01 MJS= 4.389E-01 XTB= 1.022E+00 EG = 1.120E+00
    + XTI= 1.780E+00 KF = 45.00E-16 AF = 1.000E+00 FC = 8.273E-01
    *
    .ENDS   
    $

     

    Best regards,


    Xavier

     

     

  • Thank you!

    But the modified model doesn't seem to be correct, there are duplicated nodes ( e.g. node 11, 12 ,21...) , and no outA, outB node,

    I am not sure, I guess maybe use two .SUBCKT may be better.

    Thank you very much!

     

     

     

     

     

  • You are correct, all the other duplicate nodes would have to be renamed as well.