Everybody is good

Hi,

I am trying to help, but I didn't understand your question very well. Can you tell me which part are you using? Do you want to chang the output current ? and what is your schematic? That may help a lot. Thank you.

5468.VS_125.01.pdfThank you

I was doing research on piezoelectric acceleration sensor, I want the output into a current output is the output of 4-20mA

I want to convert piezoelectric acceleration sensor to 4-20 ma output

Piezoelectric acceleration is the output of the ac voltage signal mv/g, but how do I convert him to 4-20 ma output?

Which the teacher can teach me

Are you designing a circuit to realize the function of the product you attached in the pdf?  What is the sensor(Piezoelectric acceleration) you are using ? what is the output range of your sensor?

Honestly speaking, I didn't design that before. I suggest you can search from the internet to get more information. What comes to my mind is that you can rectified the output of the acceleration sensor (AC signal) to a DC signal , and then detect the peak value of the rectified signal. Use the  DC signal to control the 4-20mA output. You have many options of using our TI products XTR to realize that 4-20mA output.

http://www.pcb.com/TechSupport/tech_signal

Piezoelectric accelerometer is the charge output signal, I put him into a voltage signal, the voltage signal, and then converted to 4-20mA output,

The charge to voltage can be, but how can I convert current signal?

Isn't there a teacher know ah

Shuai Chen,

As mentioned above, you should look at our 4-20mA current loop transmitter ICs. Probably the most simple to use would be the XTR117. You would need to place a resistor in series with the output of your charge amplifier to convert the signal into a current for the XTR117. Check out the XTR117 datasheet to calculate the appropriate value.