On page no. 27 of application note "Signal conditioning for piezoelectric sensors" in first bullet point on left hand side of figure 6, I want to know how the value of 5.85 in the denominator have been calculated.
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On page no. 27 of application note "Signal conditioning for piezoelectric sensors" in first bullet point on left hand side of figure 6, I want to know how the value of 5.85 in the denominator have been calculated.
Hi Miheer,
In this application note you noted:

The page 4 expression involving "5.85" in the denominator is the result of evaluating Equation 7 at 5Hz:
From Figure 6 schematic:
RFB= 270M
CFB = 680pF
So, the denominator "value" at f = 5Hz is:
SQRT (1+ [(270M). (680pF). 2*pi(). 5Hz]^2) = SQRT (34.3) = 5.85
Hope this answers your question.
Regards,
Hooman