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Hello,
Here is my dilemma, when applying a low signal (near ground), my output of the LM2907 is not zero and the voltage varies,
I am using the tachometer with minimum component.
My voltage supply is 12.5V
R1 = 100K
R2 = 10K
C1 = 0.1uF
C2 - 1uF
the device is very linear and works from a frequency input of 3 - 30Hz. But when a low ground signal is applied, my output is not at zero.
Thanks, for the help.
-Gary
Hello Gary,
The lower output level VOL of the LM2907-N behaves as described in Note 2, located just below the 7.5 Electrical Characteristics table, on Pg. 6. This is what Note 2 states:
(2) VOH = 0.75 × VCC – 1 VBE and VOL = 0.25 × VCC – 1 VBE, therefore VOH – VOL = VCC / 2. The difference (VOH – VOL) and the mirror gain (I2 / I3) are the two factors that cause the tachometer gain constant to vary from 1. Therefore, if VCC is set to 12.5 V, VOL will be about 2.43 V.
If you can follow the LM2907-N with a comparator, then you could have a near 0 V output on the low end and VCC (of the comparator) on the high end. If you need a comparator suggestion I can help.
Regards, Thomas
Precision Amplifiers Applications Engineering
Hi Thomas,
It seems I am not getting linear results when a frequency from 15Hz down to 0Hz.
From 15Hz to 30Hz, the voltage output is a clean 2.5V to 5V.
15Hz down to 0Hz, there seems to be a 200mV offset. Would have an average output of 2.2V instead of 2V.
The results are a little worse when the Amplitude of the input sine wave is decreased.
My frequency input is not exactly centered around 0V. Would this matter?
Thanks for any advice and tips,
Gary
Hi Gary,
Please make sure that you have selected the components external to the LM2907-N for best performance over the intended input frequency range. Pages 2 through 6 of the Applications Note 162 are especially informative. If you haven't seen the applications note, you can find it here:
Once you have setttled on your design and if you find the performance still isn't satifactory, then post the circuit diagram showing the input conditions, the supply levels and output load.
Regards, Thomas
Precision Amplifiers Applications Engineering