This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

ACF2101: what is the current measurement capability of this part ? (positive and negative range in pA / nA) (Cint = 50pF, integration time = 50ms)

Part Number: ACF2101


What are the current measurement capabilities ?  Can it can measure both positive and negative currents as long as voltage at output doesn't get saturated ?

Also, what are the voltage levels that Vdd, VEE pins (and Input pins ) can support ??

Application details:

I am looking to use this part as part of my leakage measurement circuitry.

Will be using the external capacitor of 50 pF and integration time of 50ms (or lower if measurements are repeatable)

My concern is the limited voltage range at the output of AFC device ! Since it can only go till +0.5V, this would mean i won't be able to measure any currents which will produce output greater than 0.5V at output (negative currents - as far current direction into AFC pin is concerned)

{for my calculations, the voltage gets to 500 mV or + 0.5 V for negative currents using equation in the data sheet and values specified above }

Please let me know if this is correct?

 

  • Hello Gaurang,

    Yes, you do not want the voltage at your output to saturate in order to achieve practical results. This means you would want to be within an output voltage range of -10V to 0.5V.

    The ACF2101 can handle an input range of +/- 100uA.

    The supplies can handle a maximum voltage level of +/- 18V. The maximum input voltage of the device is not specified, but it should not produce an input current of +/-5mA into the device.

    Using the Vout equation shown below and using the integration time and capacitance you specified, it would seem that you will be able to measure an input current range between -10nA to 500pA without saturation. You will not achieve any positive voltages when inputting a negative current.

    Depending on your desired input current range, you may want to change you integration time or integration capacitance.

    Best,

    Hasan Babiker

  • Thanks for the response!

    This helps..

    Regards,

    Gaurang