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TLV9061: TLV9061 as charger

user503335153
Intellectual 810 points
Part Number: TLV9061
Other Parts Discussed in Thread: TLV9062

In my watch project, I use TLV9061 as a supplementary charging device. But there are some questions I want to confirm: 1. In the case of V + suspension and V - grounding, what is the state of Vout port and whether it is in high resistance state? For example, if Vout is connected to the battery voltage, will there be leakage current in this state, and is there a risk of burning down the device?

2、In the working state, if the Vout voltage is less than V+, the short circuit current is 50 mA. If the maximum output current is reached, will the chip protect and turn off the output? Or will it lower the voltage? Can the battery charge function be realized?

  • 0
    TI__Guru**** 152176 points

    User,

    Answer 1)  I measured V+ voltage and output current when V+ was open other than a 10M ohm resistor to ground versus and external voltage applied to VOUT.   I used a TLV9062 which will be a similar result to TLV9061. output voltage will leak to V+ and will power up the TLV9061.

    This is output pin current vs. output pin voltage. Current is significant when OUT > 1V.

    (L) means out wants to go low, IN- >IN+;  (H) means out wants to go high, IN+ >IN-

    This is V+ voltage vs. output pin voltage. Output voltage leaks back to V+

    (L) means out wants to go low, IN- >IN+;  (H) means out wants to go high, IN+ >IN-

    Answer 2)   Sorry the question is not clear. Try looking at figure 10 in the data sheet. Short circuits should a rare faults occurrence. Short circuit is not meant to be a normal operation method. The device does not shut down if op amp overheats.  

  • 0 in reply to Ron Michallick
    TI__Guru**** 152176 points

    Here is some circuitry (SD1) to prevent battery discharge (other than a couple microamps) and limit short current (R2)