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As per the datasheet recommendation we are planning to use Supply voltage (VS) as 5V (VS+ = 2.5 V, VS– = –2.5 V).
we are planning to use amplifier LMH5401 as ADC driver and single ended 50-Ohm input to 200Ohm differential output.
For maximum Input voltage range at (VS & VS+) is mentioned as (VS–) – 0.7 and (VS+) + 0.7. So we can take it as VS+ = 3.3 V, VS– = –3.3 V as absolute maximum input levels.
Now we have assumed our input is 50Ohm matched (single ended) and for maximum of +/3.3V (6.6Vp-p) if we calculate for 50 Ohm load the input power will be +20.4dBm.
Can we take +20.4dBm as absolute maximum RF input power when we use Supply voltage (VS) as 5V (VS+ = 2.5 V, VS– = –2.5 V)? Is it our above calculations are correct?
