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INA233: How to use trigger function to get the 0.3msec current pulse?

Part Number: INA233


Hello TI teams,

Nice to see you.

We would like to use the INA233 to get the current pulse which current would be smaller than 1mA of photo diode.  

And the frequency of our current pulse would be 30Hz / Duty Cycle 0.9% / Pulse on 0.3msec (which means 0.3msec on / 32.7msec off in one peroid).

The coeiffeicent which we used in INA233 as below:

Current_LSB = 1000uA / (2^15) =  3.05 x 10^ -8

CAL = 0.00512 / Current_LSB * R = 0.00512 / (3.05x10^-8) * (80.6 ohm) = 2081.54 -> Hex: 0x0822

We could sense the costant current about 500uA already in continue mode.

We try to measure the current pulse  in 500uA / Pulse on:0.1sec, Pulse off: 0.1sec,

and set the number of average(AVG) as 1,

But we get the result as below:

a. 300usec conversion time = 370uA (4097h) in continue mode 

b. 100usec conversion time = 199uA (4007h) in continue mode

Could you please help us how to set the right register setting of trigger mode to get the pulse max. current value? 

Please kindly to help us.

Thank you so much.

The application and schemaic design as below:

Best regards,

Muller

 

  • Hey Muller,

    Welcome to the Amplifiers Forum. Thanks for posting your question.

    100us and 300us conversion times should be plenty fast enough for the situation you were describing (100ms on time, 100ms off time, so 5 Hz). The INA233 should also be able to measure peak current when the ON time is 300us, but you will want to choose a shunt voltage conversion time of 140us during this configuration.

    Anyway, are you sure that you are calculating your current measurements correctly? If current register reads back 4097h (16535 dec) and 4007h (16391 dec) and you multiply the decimal values by the current LSB (ILSB=30.5nA), then this calculates to 504.3175uA and 499.9255uA respectively.

    If I am mistaken, please respond back with some data showing the peak current is actually reaching 500uA.

    Sincerely,
    Peter Iliya