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LMC6442: Leakage Current input/output pin to (V+)/(V-) pin

Part Number: LMC6442

Dear Specialists,

My customer is considering LMC6442 and has a question.

I would be grateful if you could advise.

---

Regarding  LMC6422

(1) When a non operating voltage (0V to 1.8V) is applied between the V + and V- terminals,

Voltage is applied to Input pins ± IN_A, ± IN_B or Output pins OUT_A, OUT_B,

Does current flow through the V + or V- terminals ?

(2) Does current flow when the maximum rating of the input / output terminals is within the range of (V +) + 0.3V and (V-) -0.3V?

(3)Would you please have a diagram of the internal circuit configuration if possible?

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I appreciate your great help in advance.

Best regards,

Shinichi

  • Hey Shinichi, 

    I believe this article provides the illustrations you are asking for: 

    All the best,
    Carolina 

  • Hi Carolina,

    Thank you for your reply.

    I read the article and have several question.

    I would be grateful if you could advise.

    ---

    (1) Is the internal circuit of the LMC6442 similar to Figure 1 in the article?

    (2) Is an clamp diode connected between the output pin and the V + / V- pin?

    (3) The absolute maximum rating of the input/output voltage of LMC6442 is (V-)-0.3V (V +) + 0.3V.

    Does this mean that the Vf of the internal diode is 0.3V?

    (4) Even when 0 to 1.8V is input, does the input exceeding (V-)-0.3V (V +) + 0.3V flow out to V + and V-?

    ---

    I appreciate your great help.

    Best regards,

    Shinichi

  • Hello Shinichi, 

    I am not sure about the specific internal circuitry of the LMC6642 since the datasheet is not very descriptive. However, I also found this article that may also prove useful about your customer questions: 

    Why does the customer need to know the internal circuitry? What are they trying to accomplish?

  • Hi Carolina,

    Thank you for your reply.

    According to the datasheet, I guess the input pin and output pin have protection clamp diodes to V+/V- pin.

    This is very important for the customer.

    Could you please confirm to other members.

    I appreciate your great help and cooperation.

    Best regards,

    Shinichi

  • Shinichi,

    For input or output voltage outside of the supply rail, current will be split between V+ and V-.  For both >V+ and <V- cases, current will flow through both pins. I do not have data for the split percentages. In semiconductor there is a saying "there is no such thing as a diode". That means every diode prefers to act as a bipolar transistor with the '3rd lead' being any nearby node.     

    The AMR table is 5mA, so it is better to keep this current below 500uA. The actual diode voltage varies with the temperature.

  • Hi Ron,

    Thank you for your reply.

    I thought there were clamp diodes on the input and output pins.

    The absolute maximum ratings of the input and output pins are (V +) + 0.3V and (V-) -0.3V.
    It was thought that when a voltage exceeding (V +) + 0.3V and (V-)-0.3V was applied, the voltage would exceed Vf of the diode and current would flow toward V + and V-.

    You mentioned that when <(V-) is input with> (V +), current flows through both rails.

    In the case of LMC6442, does it mean that there are no clamp diodes on the input and output pins?

    I appreciater your great help.

    Best regards,

    Shinichi 

  • Hi Shinichi,

    yes, there ARE ESD clamps from the inputs and outputs to the rails and they are very probably ESD diodes. But they can interact with the intrinsic substrat diodes or can be part of a more complex circuit interacting or not with the substrat diodes. So thinking of having simple diodes there might be a too simplistic assumption and can cause trouble when treating them as simple diodes.

    Kai  

  • Shinichi,

    For when current flows, think of a diode. For where the current flows, be prepared for it to go to V+ or V- 

    300mV is the specified voltage because little (safe) current will flow even at the highest allowed temperature.  

    We could help better if the factor that lead to this question was explained.

     

  • Hi Kai and Ron,

    Thank you for your reply.

    I'm sorry for the late reply because I was off on the weekend.

    I understand internal clamp diode can act as another circuit.

    I'll share this information with the customer.

    Also I confirm the background of this question.

    I'll feedback to you when I obtain.

    I appreciate your great help and cooperation.

    Best regards,

    Shinichi 

  • Hi Ron,

    I could obtain the background of the customer's question.

    ---background
    When the power of amplifier circuit ​​is turned off in the state of the circuit configuration,
    I am concerned that the electric charge remaining in the ceramic capacitor mounted on the circuit may destroy the amplifier.

    ---

    Would you please confirm the schematic.

    Could you please contact my e-mail  address listed below.

    <email address removed>

    I appreciate your great help and cooperation.

    Best regards,

    Shinichi

  • Shinichi,

    I sent a friend request. Once we are "friends" we can share privately.

  • Hi Ron,

    Thank you for your reply.

    I just accepted friendship.

    I'm preparing the materials.

    Then I send you.

    Could you please wait for a while.

    I appreciate your great help and cooperation.

    Best regards,

    Shinichi

  • Shinichi,

    None of the capacitors in the circuit store enough energy [1/2 * C * V^2] to damage the op amp. Even if the supply during turn off is a hard short (opposed to a more gradual decay) the input and output pin resistances will be high enough to limit current to a reasonable value.  

  • Hi Ron,

    Thank you for your reply.

    I understand capacitor and resistor value look good.

    I'll share this information with the customer.

    I appreciate your great help and cooperation.

    Best regards,

    Shinichi