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Hi
please see below:
for non-inverting: BW = GBW / (1+R1/R2), right?
for inverting: also BW = GBW / (1+R1/R2), right?
thanks
Hello,
You are correct in using the non-inverting gain to calculate bandwidth in both circuits (BW = GBW/ Non-inverting Gain).
For the schematics provided, the first circuit would posses an equation of BW = GBW/ (1+ R3/R2), and the second circuit, BW = GBW/ (1+ R5/R6).
If you need further resources for bandwidth calculation, this TIPL video offers lots of information on BW calculation and why inverting amplifiers use noise gain/non-inverting gain for BW calculation.
Let me know if you have any further questions,
Regards,
Jacob
Hey Jian,
Your noise gain expressions are correct above, however the GBP analysis is a considerable oversimplification, came up again this AM on this thread you might find interesting,