I am Refering to TI's application report titled "AC Coupling Between Differential LVPECL, LVDS, HSTL and CML signals" . Here is link to it:
http://www.ti.com/lit/an/scaa059c/scaa059c.pdf
On page 7, Figure 11, it is showing LVDS to LVDS AC coupling,
I have couple of questions on this:
(1) Should not the two caps be on right hand side of the 100 Ohm termination resistor? I thought, LVDS standard requires a DC current loop with return path to the transmitter (even when AC coupled). If 100 Ohm resistor is on left hand side of two caps, then DC has return path via resistor.
May be my understanding is not right. Can some one clarify?
regards