• State TI Thinks Resolved
  • Locked Locked
  • Replies 4 replies
  • Answers 3 answers
  • Subscribers 33 subscribers
  • Views 252 views
  • Users 0 members are here
Support feedback
Options
Options
Similar topics

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

AM26C32: Differences between AM26C32IPWR and AM26LS32ACPWR, and what are the concerns when replacing them

Conor
Guru 10665 points
Part Number: AM26C32
Other Parts Discussed in Thread: AM26LS32AC

Hi, 

Customer has adopted AM26C32IPWR but needs to replace due to availability. They are considering AM26LS32ACPWR as a replacement product.

What are the differences between AM26C32IPWR and AM26LS32ACPWR, and what are the concerns when replacing them?

Thanks,

Astro

  • 0
    Guru 297310 points

    The AM26C32 was designed as a replacement for the AM26LS32AC. The LS uses five times more power.

  • 0 in reply to Clemens Ladisch
    Guru 10665 points

    Since each datasheet is different, is it possible to tell me the difference as much as possible? It seems that the temperature range and current consumption are different. 

  • 0 in reply to Conor
    Guru 297310 points

    The LS device has higher power consumption, a narrower temperature range, a wider input voltage range, a slightly slower speed, and a lower output voltage (TTL, so it will not be able to drive a 5 V CMOS input).

  • 0 in reply to Conor
    TI__Mastermind 48327 points

    Hi Astro,

    The high level differences are shown below:

    The AM26LS32AC has a lower operating temperature, consumes a max of 70mA (compared to the 15mA) for ICC, but has a higher abs max for differential bus inputs. 

    These are the largest differences for operation between the parts. So there is risk with the largest being the lower temperature range as <0C for the operation is out of spec for the "AC" device. 

    Please let me know if there are any other questions!

    Best,

    Parker Dodson