Other Parts Discussed in Thread: DP83869
HI there,
I hope you are well,
I have some questions regarding the correct way to connect this device inline with 2 ethernet connectors (RJ45), as if this device was in the middle of a cable or PCB backplane. I have had a look at the EVM schematic and it has thrown some confusion to my normal understanding of RX/TX pairs, as the TX lines from the QSFP device are connected to the TX lines of the DS250F810 and the same fort he RX lines.
Here's a brief overview of my usage scenario:
I have 2 ethernet connectors (RJ45) I currently have connected them pin to pin as a passive Ethernet cable extender, I want to also build a device that will allow me to make an active ethernet extender, with the DS250F810 in the middle of the 2 RJ45 connectors and Pin to pin linked, such that from the perspective of the connected devices it would be like it was just a standard cable connected, just with an inline signal conditioning capability.
Questions
1. Do I connect RX+/- from ethernet RJ45 TO RX +/- of DS250F810 or is it RX+/- of Ethernet RJ45 connector to TX+/- of DS250F810 and vice versa ( I have attached a PDF to illustrate these examples)0652.DS250F810 LAYOUT EXAMPLES.pdf
Please let me know which example (1 or 2) is correct :).
2. is there a programming guide/example code I can use with the VSCode/Arduino environment/STM32, or any code I can port myself?
Thank you in advance for any advice :).
Kind regards
Wes