Dear team,
customer study our app note - SNLA267A.
And they have a question about *2.1.1.5 Clocking and Frequency Selection Example*.
There is a constant value 80 in FC rate equation.
Could you guide us the *80* comes from? How we get this constant value?
FC Rate = 2×80(f0 ) = 160(25M) = 4 Gbps
Regards,