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TXS0104E: logic level translator for I2C and I2S

Shibin Varghese
Intellectual 835 points
Part Number: TXS0104E
Other Parts Discussed in Thread: TXB0104, TXS0102, SN74AXC4T774, SN74LVC125A

Hi Team,
We are using TXS0104E in one of our projects for level shifting a 3.3V I/O signal to 1.8V I/O logic.
My controller is a 3.3V I/O logic controller.
The end device is an audio amplifier.TLV320DAC3101IRHBT.
It has both I2S and I2C interfaces.
1). Is the IC TXS0104E, the good choice for my application.
2). Is there any 6 channel IC available for my purpose since we have 6 such signals from the TLV320DAC3101IRHBT to the MCU?.
3). I believe TXS0104E  is the best choice for I2C and I2S.
4). I believe I don't require any external pull-up resistors for I2C as they have integrated pull-up resistors to corresponding voltage levels.
5). I believe the IC TXS0108EPWR is an 8 channel variant of the IC TXS0104E, but it is not available in Mouser or Digikey.
6). Do I need to use TXB0104 for the push-pull application?. because this seems more suitable with mu application.

  • 0
    TI__Mastermind 45045 points

    Hey Shibin,

    I recommend using TXS0102 for the I2C signals and then using the SN74AXC4T774 for the I2S signals. That would give you your 6 channels.

  • 0
    Guru 295240 points

    If all four I²S signals are inputs to the codec, then you can simply use a buffer with overvoltage-tolerant inputs (e.g., SN74LVC125A) for level shifting.

  • 0 in reply to Clemens Ladisch
    Intellectual 835 points

    Hi Team,
    Thank you for your reply.
    The IC SN74AXC4T774BQBR seems like a good option. However, it will need at least another 4 pins for direction control and an OE pin.
    All the OE pins and the direction control pins are referred to as VCCA.In my case, VCCA will be 3.3V and VCCB will be 1.8V. I hope there is no issue when VCCA is treated than VCCB.
    Is there any IC available without such direction control pins?. 

  • 0 in reply to Shibin Varghese
    Guru 295240 points

    The DIR/OE pins are overvoltage tolerant, but do not accept voltages lower than VCCA.

    Just rotate the chip to exchange the A and B sides, so that VCCA is the lower voltgage.

  • 0 in reply to Clemens Ladisch
    Intellectual 835 points

    Hi CL,
    Thank you for your reply.
    I am sorry I didn't understand your reply.
    Did, you mean connecting the VCCA port to the low voltage side (1.8V) and the VCCB pin to the high voltage side (3.3V)?.
    Also, Is there any IC available without such direction control pins?. 

  • 0 in reply to Shibin Varghese
    Guru 295240 points

    Yes; if VCCA is the low voltage, the control pins can be connected to either voltage.

    Why do you want a device without control pins? You do not need to set the control pins from the microcontroller; it is allowed to connect them directly to VCC or GND.