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Original question:
TIDM-02009: Please tell us about the DC to DC Boost switching method.
Tool/software:
I am studying power electronics for the first time. We would like to implement a Boost converter by producing a 3.6Kw DC to DC of TIDM-02009. It is questionable whether the current capacity of the inductor and transformer applied to the circuit is correct.
Based on my narrow insight, I simply calculated that the capacity of the inductor would be around 330A, and that the transformer would have at least 9A on the primary side and 330A on the secondary side. However, the inductor and transformer used in TIDM-02009 seem to have a current capacity of about 1/10th. Could you please explain regarding the above? I'm new to power electronics and there are still many things I don't know. Please help me understand.