led blink using timer

The compiler is telling you that it does not know what is TACTL_bit.TAIFG, You have two options to fix this problem:

1. Do not use TACTL_bi.TAIFG

2. Define what you mean by TACTL_bit.TAIFG

I think by TACTL_bit.TAIFG you are trying to check if there are any timer interrupt but this syntax is not defined in the header file.

You can replace it with TAIFG only, but it is better to use an interrupt service routine which you can find from the example codes provided from TI. 

Regards

Gunay

i am new to c programming till now i have just been working with assembly i dont know much about c..can u help me on what is the syntax for accessing individual of a register in ccs ??

which header contains details about accessing individual bits of a register ??

You probably do not have such a header file. And that is why you got that error msg to begin with.

Usually, TACTL is defined and TAIFG is defined too. Thus TACTL & TAIFG can be used instead of the undefined TACTL_bit.TAIFG

WITH UR HELP I WAS ABLE TO ELIMINATE THE ERROR BUT STILL NOT GETTING THE OUPUT ..

THE CHANGED CODE IS..

/*
* main.c
*/
#include<msp430g2553.h>
#define LED1 BIT0
#define LED2 BIT6
void main(void)
{
WDTCTL = WDTPW | WDTHOLD;
P1DIR = LED1 |LED2;
P1OUT = LED1 |LED2;
TACTL = MC_2 | ID_3 | TASSEL_2 |TACLR | TAIE ;
for(;;)
{
while(TACTL&TAIFG == 0)
{

}
TACTL^=TAIFG;
P1OUT ^=LED1 |LED2;
}
}

It worked :D.. thank you for ur help :)

You are welcome.

BTW, you set the TAIE bit in TACTL. This is unnecessary and should be avoided when you do not have an ISR to handle it. But fortunately, you did not set GIE, so TAIE did not hurt you.

Also, you use TACTL ^= TAIFG; to reset that flag. It works only when it was set (as in you case). It is cleaner to use TACTL &= ~TAIFG; to reset the flag.

will taken in these considerations and will make changes to the program code .