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Hello,
We are planning to use the TPS548B28 switcher for a new design.
Pin# 20 is the output pin and is only 0.35mm wide. I'm sure I'm not understanding something but how is such a narrow width supposed to be able to deliver up to 20 amps?
Here is the link to the datasheet:
The package outline is on page 45.
We're on a tight schedule so your prompt reply is greatly appreciated!
Thanks!
Bill
Hi Bill,
Pin 20 of the TPS548B28 is the SW node, which doesn't exactly deliver the 20 A output current. The SW sends PWM signals to the output inductor which maintains a steady output current. The image below shows the relationship between the PWM signals from SW and the inductor current. I also included an application note on switching regulator principles.
Switching regulator fundamentals (Rev. C) (ti.com)
Best,
Ryan
Hi Ryan,
Thank you for your prompt reply. If not pin 20, then from which pin does the 20A flow from?
Thanks,
Bill
Hi Ryan,
Thank you for your prompt reply. If not pin 20, then from which pin does the 20A flow from?
Thanks,
Bill
Hello Bill,
yes, the pin can handled the rated current according to datasheet. It can do maximum peak inductor current of 35A. The qualification process confirms that the reliability of our products, processes, and packages meets industry standards. All TI products undergo qualification and reliability testing or qualification by similarity justification prior to release. Common questions about TI’s qualification process can be found here.
For this device in particular, it's been in the market since 2020 with no returns or any quality issues. As long as the datasheet spec are meet in your design and the recommended operating conditions are followed, the device will handle the current ratings.
Thanks
Tahar