This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

LM25119: Power Delivery Efficiency - request for data/clarifications

Part Number: LM25119
Other Parts Discussed in Thread: PMP10979,

Hi,

I'm searching for a very high efficiency DC-DC buck converter for a new design, with the following parameters:

Vin = 12V or 24V

Vout = 2.4V,nom

I,out,nom=25A

I,out,max=40A

Searching TI parts, I notice the LM25119 has a reference design, PMP10979 with a purported 98% efficiency (condition dependent, see chart below taken from PMP10979 Test Results):

https://www.ti.com/tool/PMP10979?keyMatch=&tisearch=tidesigns-power&keyMatch=pmp10979&tisearch=Search-EN-Everything#overview

However, when I used WeBench for my design, the tool tells me to expect a max efficiency of 92.4% (I used my own design requirements as stated above).

Here are some questions:

(1) Why is there such as difference in efficiency between these test results and the WeBench?

(2) Is more data available for the LM25119, for example an efficiency graph for a single device (I recognize the PMP10979 is 4-phase with 2 devices, instead of a 2-phase 1 device design)?

(3) Is there a different VR that may be more efficient and more suitable for my design?

Thanks,

Tom

WBDesign-LM25119-12Vin-2p4Vout-40A-92p4Eff.pdf

  • Adding an efficiency graph I found in the LM25119 datasheet. I don't know if this is interleaved or not...? And it is only 8A max load current.

    Also, there is still the discrepancy with the reference design. Please assist.

  • Hello,

    The efficiency depends on circuit parameters. For comparing the result:

    1- Same power FET should be used

    2- same inductor

    3- same sense resistance

    4- same switching frequency

    5- same output voltage

    6- same load current

    6- same input and output capacitance

    7- same input voltage

    The controller power loss is supply voltage times quiescent current: VCC*ICC. All the other loss depend on the above parameters.

    Regards