I have read TPS65273V datasheet. As I understand it, when the output voltage is set with a resistive divider via FB pin, the output voltage can be up to 15V. But, when it is set via I2C, the VOUT pin is directly connected to the output node and therefore the voltage limited to 1.95V. Is it possible to connect VOUT pin to the output node through a resistive divider in order to reach voltages higer than 1.95V? I would like to use voltages in the 3.3 - 4 V range.
Thank you for you help
Hi, Ricardo
In theory, you can add a resistor to increase the output voltage, see below.
But there is a risk:
Due to the internal divider resistor is matched well, under different temperature, different corner, the ratio of internal divider resistor is fixed, TI can assure the Vout accuacy without external resistor.
But the external resistor is independent of internal divider resistor, so under different temperature, different corner, Vout will have big variation.
So not recommend to use TPS65273V in this way.
