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Original question:

TL4050A50-Q1: TL4050A50-Q1

TL4050A50-Q1: How to use the TL4050 following conditions

Masayuki Uchihara
Intellectual 1676 points
Part Number: TL4050A50-Q1

Team,

Could you make sure whether my calculate is correct or not in below conditions.

Must:

- Vs=6V to 36V

- Vz=5V

- Iout>50mA

Accuracy >0.5%

My calculation is as below

Iz is chosen from datasheet spec of the minimum cathode current.

Is it okay to use the Rs value even the Vs should be changed from 6V to 36V?

If yes, how do I realize the above condition?

Thanks,

Uchihara

  • 0
    TI__Genius 11391 points

    Hi Uchihara 

    Max value of Rs will be decided by Load current + Knee current . Minimum value of RS will be decided by max IZ (15mA )

    for RS MIN

    VS= 36 V

    VZ = 5V

    IZ = 15mA

    IL = 50mA

    RS = 31/65 = 476 ohm 

    Now  IZ min = 90uA 

    RS = (VS-VZ)/(IZ + IL) = 

    VSMIN = RS * (IZ + IL) + VZ = 0.476 (50.090) + 5 = 28.8V

    Hence RS =  476 ohm will support only VS = (28.8V , 36V).

    Regards

    Trailokya