• State TI Thinks Resolved
  • Locked Locked
  • Replies 1 reply
  • Answers 1 answer
  • Subscribers 63 subscribers
  • Views 151 views
  • Users 0 members are here
Support feedback
Options
Options
Similar topics

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TLV742P: Forward voltage of the body diode

sho
Prodigy 40 points
Part Number: TLV742P

Hi team

I want to step down 5V (Vin) to 3.3V (Vout) using TLV742P（TLV74233PDQNR）.

I use 5V as the power supply (Vdd) and 3.3V as the pull-up voltage (Vsignal) for another IC.

If 5V is interrupted, Vsignal> Vdd due to the residual voltage.

The rating of this IC is Vsignal> Vdd + 0.3V, so I need to insert a diode between the Vout-Vin pins of the TLV742P.

Can you disclose to me the data of the forward voltage of the body diode inserted in the package of TLV742P?

For other measures, I have placed a pull-down resistor near Vout.

As a result, the time it takes for Vout to discharge is designed to be about 0.16 μs.

Regards,

  • 0
    TI__Genius 13175 points

    Hi,

    the device is rated at Vout<=Vin+0.3V to keep the current flowing through the body diode very small however the forward voltage where it starts to conduct a large amount of current will be closer to 0.6V. So if you parallel diode has a forward voltage of ~0.4V, that will ensure that the external diode carries almost all of the reverse current. 

    Since you have 2.7V from Vin to Vout you may also be able to use a blocking diode on the input before the LDO and input capacitor, if that is easier for your application. This configuration will also reduce the power dissipation and junction temperature of the LDO.